What is the change in energy if the electron from part a now drops to the ground state? what is the wavelength λ of the photon that has been released in part b?

Question

Chemistry

Zimmerman

27 June, 06:03

What is the change in energy if the electron from part a now drops to the ground state? what is the wavelength λ of the photon that has been released in part b?

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Marc Potts · Answer 1

Change in energy: ΔE = E1 - E4

E1 = - 13.6 eV (1.602 x 10^-19 J/eV) / 1^2 = - 2.18 x 10^-18 J

ΔE = - 2.18 x 10^-18 J - (-1.36 x 10^-19 J) = - 2.04 x 10^-18 J

Wavelength of the photon: E = hν = hc/λ, where h = Planck's constant and v = frequency in s^-1; λ = wavelength in m, and c = 3.00 x 10^8 m/s

2.04 x 10^-18 J = (6.626 x 10^-34 J*s) (3.00 x 10^8 m/s) / λ

λ = (6.626 x 10^-34 J*s) (3.00 x 10^8 m/s) / (2.04 x 10^-18 J) = 9.74 x 10^-8 m