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14 June, 07:49

What is the molality of a solution that contains 5 moles of solute in 100 kilograms of water?

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  1. 14 June, 08:00
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    molality = (moles of solute) / (kilogram of solvent)

    moles of solute = (75.2 g AgClO4) / (mole mass AgClO4)

    moles of solute = (75.2 g AgClO4) / (207.3206 g/mol)

    moles of solute = 0.3627232 mol

    molality = (0.3627232 mol) / (0.0752 Kg)

    molality = 4.8234468 m or 4.82 m rounded to three significant figures
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