What mass of magnesium chloride is needed to make 100.0 mL of a solution that is 0.500 M in chloride ion?

M = n/V

.5M = n/.100 L

n =.1 L *.5M

n =.05 mols of MgCl2

mass of MgCl2 =.05 mols of MgCl2 * 95.211 grams / 1 mol of MgCl2

mass of MgCl2 = 4.76 grams

4.76 grams of MgCl2 is needed to make 100 ml of a solution that is. 500M, in chloride ion. Bolded = confused