How many liters of nitrogen gas are needed to make 25 mol of nitrogen trifluoride

The reaction between N₂ and F₂ gives Nitrogen trifluoride as the product. The balanced equation is;

N₂ + 3F₂ → 2NF₃

The stoichiometric ratio between N₂ and NF₃ is 1 : 2

Hence,

moles of N₂ / moles of F₂ = 1 / 2

moles of N₂ / 25 mol = 0.5

moles of N₂ = 0.5 x 25 mol = 12.5 mol

Hence N₂ moles needed = 12.5 mol

At STP (273 K and 1 atm) 1 mol of gas = 22.4 L

Hence needed N₂ volume = 22.4 L mol⁻¹ x 12.5 mol

= 280 L