How many moles in 43 liters of co2 at stp?

Let's assume that CO₂ has ideal gas behavior.

Then we can use ideal gas formula to solve this.

PV = nRT

Where,

P = Pressure of the gas (Pa)

V = Volume of the gas (m³)

n = moles of the gas (mol)

R = Universal gas constant (8.314 J K⁻¹ mol⁻¹)

T = Temperature in Kelvin (K)

In this problem,

P = Standard pressure = 1 atm = 101325 Pa

V = 43 L = 43 x 10 ⁻³ m³

R = 8.314 J K⁻¹ mol⁻¹

T = standard temperature = 273 K

n = ?

PV = nRT

By rearranging,

n = PV / RT

n = (101325 Pa x 43 x 10⁻³ m³) / (8.314 J K⁻¹ mol⁻¹ x 273 K)

n = 1.92 mol

Hence moles of CO₂ gas in 43 L at STP = 1.92 mol