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12 December, 17:21

You buy helium gas in small pressurized cans to inflate party balloon. The can label indicates that the container delivers 7100 ml of helium gas at 100.0 kpa pressure. The volume of the gas container is 492 ml

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  1. 12 December, 20:34
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    Looking at the problem, we can say that this is a problem involving ideal gas equation. We are given 2 data for pressure and one volume. Assuming that the temperature for both cases is the same, we can use Boyle's Law to find the pressure.

    P₁V₁ = P₂V₂

    (100 kPa) (7100 mL) = (P₂) (492 mL)

    Solving for P₂,

    P₂ = 1,443.09 kPa
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