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3 January, 07:17

When heated, calcium carbonate decomposes to yield calcium oxide and carbon dioxide gas via the reaction caco3 (s) →cao (s) + co2 (g) what is the mass of calcium carbonate needed to produce 61.0 l of carbon dioxide at stp? express your answer with the appropriate units?

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  1. 3 January, 10:01
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    Answer is: 227.3 grams of of calcium carbonate needed.

    Chemical reaction: CaCO₃ → CaO + CO₂.

    V (CO₂) = 61.0 L.

    n (CO₂) = V (CO₂) : Vm.

    n (CO₂) = 61 L : 22.4 L/mol.

    n (CO₂) = 2.723 mol.

    From chemical reaction: n (CO₂) : n (CaCO₃) = 1 : 1.

    n (CaCO₃) = 2.273 mol.

    m (CaCO₃) = n (CaCO₃) · M (CaCO₃).

    m (CaCO₃) = 2.273 mol · 100 g/mol.

    m (CaCO₃) = 227.3 g.
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