A 50 L cylinder is filled with argon gas to a pressure of 10130.0 kPa at 300°C. How many moles of argon gas does the cylinder contain? (Given: R = 8.314 L∙kPa/K∙mol) 2519.142 mol

To answer this question, we will use the general gas law which states that:

PV = nRT where:

P is the pressure of the gas = 10130.0 kPa

V is the volume of the gas = 50 liters

n is the number of moles that we want to calculate

R is the gas constant = 8.314 L∙kPa/K∙mol

T is the temperature = 300+273 = 573 degree kelvin

Substitute with the givens in the equation to get the number of moles as follows:

10130 * 50 = n * 8.314 * 573

506500 = 4763.922 n

n = 506500 / 4763.922

n = 106.3199 moles