02 g of a sugar (molar mass = 360.4 g/mol) is dissolved in water to make 100.0 ml of solution. what is the molarity of this sweet solution

The question states that 18.02 g of the sugar is dissolved.

Molarity of solution is defined as number of moles dissolved in 1 L.

the molar mass of sugar - 360.4 g/mol

The mass dissolved - 18.02 g

Therefore number of moles of sugar - 18.02 g / 360.4 g/mol = 0.05 mol

number of moles in 100.0 mL of solution = 0.05 mol

therefore number of moles in 1000 mL = 0.05 mol / 100 x 1000 = 0.5 mol

Molarity of solution = 0.5 mol/L