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11 November, 17:53

Calculate the mass of Octane needed to release 6.20 mol Co2

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  1. 11 November, 18:57
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    The combustion reaction of octane is as follow,

    C₈H₁₈ + 25/2 O₂ → 8 CO₂ + 9 H₂O

    According to balance equation,

    8 moles of CO₂ are released when = 114.23 g (1 mole) Octane is reacted

    So,

    6.20 moles of CO₂ will release when = X g of Octane is reacted

    Solving for X,

    X = (114.23 g * 6.20 mol) : 8 mol

    X = 88.52 g of Octane

    Result:

    88.52 g of Octane is needed to release 6.20 mol CO₂.
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