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4 June, 23:22

What volume of 0.45 M LiOH would be needed to neutralize 60.0 mL of 0.15 M Hi?

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  1. 5 June, 02:13
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    Answer is: volume of 0.45 M LiOH is 20 mL.

    Chemical reaction: LiOH + HI → LiI + H₂O.

    From chemical reaction: n (LiOH) : n (HI) = 1 : 1.

    c (LiOH) · V (LiOH) = c (HI) · V (HI).

    0.45 M · V (LiOH) = 0.15 M · 60.0 mL.

    V (LiOH) = 0.15 M · 60.0 mL / 0.45 M.

    V (LiOH) = 20 mL : 1000 mL/L = 0.02 L.

    n - amount of the substance.

    c - concentration of solution.
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