What volume of so2 is produced at 325 k and 1.35 atm when 15.0 grams of hcl reacts with excess k2so3?

The volume of SO2 produced at 325k is calculated as below

calculate the moles of SO2 produced which is calculated as follows

write the reacting equation

K2SO3 + 2 HCl = 2KCl + H2O + SO2

find the moles of HCl used

=mass/molar mass = 15g / 36.5 g/mol = 0.411 moles

by use of mole ratio between HCl to SO2 which is 2:1 the moles of SO2 is therefore = 0.411 / 2 = 0.206 moles of SO2

use the idea gas equation to calculate the volume SO2

that is V=nRT/P

where n=0.206 moles

R (gas constant) = 0.082 L. atm / mol. k

T=325 K

P=1.35 atm

V = (0.206 moles x 0.082 L. atm/mol. k x325 k) / 1.35 atm = 4.07 L of SO2