Balance the chemical equation, with the states of matter, describing the complete combustion of propane gas (c3h8).

C3H8 (g) + 5 O2 (g) = > 3 CO2 (g) + 4 H2O (g) Propane will burn in oxygen to produce carbon dioxide and water. So let's write down the initial equation C3H8 + O2 = > CO2 + H2O Now count the number of atoms of each type for each side of the equation C 3 1 H 8 2 O 2 3 Obviously they don't match. So let's look closer. I see 3 carbon atoms on the left side and only CO2 on the right consume the carbon. So let's make the equation show 3 CO2 molecules. And since I have 8 hydrogen atoms on the left and 2 on the right, let's also make the equation make 4 water molecules. So we now get C3H8 + O2 = > 3 CO2 + 4 H2O Now let's count the number of atoms on both sides C 3 3 H 8 8 O 2 10 The carbon and hydrogen look good. But we need more oxygen on the left side. Looks like 5 oxygen molecules will work fine. So we get C3H8 + 5 O2 = > 3 CO2 + 4 H2O Count the atoms again C 3 3 H 8 8 O 10 10 And everything balances. All of the reactants and products are gasses during the burning so the final balanced equation is C3H8 (g) + 5 O2 (g) = > 3 CO2 (g) + 4 H2O (g)