The value of ksp for silver sulfide, ag2s, is 8.00*10-51. calculate the solubility of ag2s in grams per liter.

When Ag₂S dissolves, it dissociates as follows;

Ag₂S - - - > 2Ag⁺ + S²⁻

First we need to calculate molar solubility which gives the number of moles dissolved in 1 L of solution.

If molar solubility of Ag₂S is y, then molar solubility of Ag²⁺ and S²⁻ is 2y and y respectively.

ksp gives the solubility constant

ksp = [Ag⁺]²[S²⁻]

ksp = [2y]²[y]

4y³ = 8.00 x 10⁻⁵¹

y³ = 2 x 10⁻⁵¹

y = 1.26 x 10⁻¹⁷ mol/L

molar mass = 247.8 g/mol

solubility of Ag₂S = 1.26 x 10⁻¹⁷ mol/L x 247.8 g/mol = 3.12 x 10⁻¹⁵ g/L

Solubility of Ag₂S = 3.12 x 10⁻¹⁵ g/L