Ask Question
16 May, 08:29

A 31.0-g sample of water at 290. k is mixed with 47.0 g water at 340. k. calculate the final temperature of the mixture assuming no heat loss to the surroundings.

+3
Answers (1)
  1. 16 May, 11:03
    0
    We will use this formula:

    M1C1ΔT1 = M2C2ΔT2

    when M1 mass of sample 1 = 31 g

    C1 for water = 4.184

    and ΔT1 = (Tf - 290)

    and M2 of sample 2 = 47 g

    C2 for water = 4.184

    and ΔT2 = (340 - Tf)

    so by substitution, we can get Tf (the final temperature):

    31 g * 4.184 * (Tf - 290 k) = 47g * 4.184 * (340 - Tf)

    ∴Tf (the final temperature) = 320 K
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A 31.0-g sample of water at 290. k is mixed with 47.0 g water at 340. k. calculate the final temperature of the mixture assuming no heat ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers