Gaseous butane reacts with gaseous oxygen gas to produce gaseous carbon dioxide and gaseous water. what is the theoretical yield of water formed from the reaction of of 5.23 g butane and of 27.1 g oxygen gas? round your answer to significant figures.

The combustion reaction for butane is as follows;

2C₄H₁₀ + 13O₂ - - - > 8CO₂ + 10H₂O

Stoichiometry of butane to oxygen is 2:13

Number of butane moles reacted = 5.23 g / 58 g/mol = 0.090 mol

number of Oxygen moles reacted = 27.1 g / 32 g/mol = 0.84 mol

we have to find which is the limiting reactant

if butane is the limiting reactant,

if 2 mol of butane reacts with 13 mol of O₂

then 0.09 mol of butane reacts with - 13/2 x 0.090 mol = 0.58 mol

there are 0.84 mol of oxygen present but only 0.58 mol reacts therefore butane is the limiting reactant.

stoichiometry of butane to water is 2:10 = 1:5

the number of water moles formed = 0.090 mol x 5 = 0.45 mol

mass of water formed = 0.45 mol x 18 g/mol = 8.1 g