Calcium carbonate reacts with hydrobromic acid to form calcium bromide, carbon dioxide, and water according to the reaction below. what is the molarity of the hydrobromic acid if 250.0 ml of it reacts with 5.64 grams of calcium carbonate?

The balanced equation for the above reaction is as follows

CaCO₃ + 2HBr - - - > CaBr₂ + CO₂ + H₂O

stoichiometry of CaCO₃ to HBr is 1:2

number of moles of CaCO₃ reacted - 5.64 g / 100 g/mol = 0.0564 mol

according to molar ratio

number of HBr moles - 0.0564 mol x 2 = 0.1128 mol

number of HBr moles in 250.0 mL - 0.1128 mol

therefore number of HBr moles in 1000 mL - 0.1128 mol / 250.0 mL x 1000 mL = 0.4512 mol

molarity of HBr - 0.4512 M