The ksp of beryllium hydroxide, be (oh) 2, is 6.92 * 10-22. calculate the molar solubility of this compound.

When Be (OH) ₂ dissolves it dissociates into the following ions

Be (OH) ₂ - - > Be²⁺ + 2OH⁻

molar solubility is the number of moles that dissolve in 1 L of solution

If the molar solubility of Be (OH) ₂ is 'x', molar solubility of Be²⁺ and OH⁻ ions are x and 2x respectively.

ksp is solubility constant for Be (OH) ₂

ksp = [Be²⁺][OH⁻]²

6.92 * 10⁻²² = [x][2x]²

4x³ = 6.92 * 10⁻²²

x³ = 1.73 * 10⁻²²

x = 5.57 * 10⁻⁸ mol/L

molar solubility of Be (OH) ₂ is 5.57 * 10⁻⁸ mol/L