Consider 2NH3 (g) + 3CuO (s) →N2 (g) + 3Cu (s) + 3H2O (g) 2NH 3 (g) + 3CuO (s) →N 2 (g) + 3Cu (s) + 3H 2 O (g). What volume (in mL) of NH3 NH 3 is required to completely react 45.2 g of CuO at STP? Enter your solution as a numerical value with no units.

Question

Chemistry

Sebastian Pollard

9 December, 14:44

Consider 2NH3 (g) + 3CuO (s) →N2 (g) + 3Cu (s) + 3H2O (g) 2NH 3 (g) + 3CuO (s) →N 2 (g) + 3Cu (s) + 3H 2 O (g). What volume (in mL) of NH3 NH 3 is required to completely react 45.2 g of CuO at STP? Enter your solution as a numerical value with no units.

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Answers (1)

Know the Answer?

Phillip Bailey · Answer 1

The volume of in Ml of NH3 required to completely react with 45.2 g of CUO at STP is 8489.6 Ml

calculation

calculate the moles of CUO used

moles = mass/molar mass

45.2 g/79.5 g/mol = 0.569 moles

Reacting equation

2NH3 + 3CUO = N2 + 3CU + 3H2O

by use of reacting ratio between NH3 to CUO which jis 2:3 the moles of NH3 = 0.569 x2/3 = 0.379 moles

At STP 1 mole = 22.4 L

what about 0.379 moles

=0.379 x22.4 = 8.4896 L

in Ml = 8.4896 x1000 = 8489.6 ml