Calculate the heat produced by combustion per liter of methanol. Methanol has a density of 0.791 g/mL.

The heat produced by combustion per liter of methanol is calculated as follows

heat released = moles x heat of combustion of methanol

heat of combustion of CH3OH = 715 kj/mol

calculate moles first

that is, moles = mass/molar mass

calculate the mass = density x volume (1L=1000ml)

= 0.791 x1000=791 g

molar mass of CH3Oh = 32g/mol

moles is therefore = 791 g / 32g/mol = 24.72moles

heat released is therefore = 24.72mole x 715 Kj/mol = 17673.91 KJ