If 18.6 ml of 0.800 m hcl solution are needed to neutralize 5.00 ml of a household ammonia solution, what is the molar concentration of the ammonia? nh3 (aq) + hcl (aq) →nh4cl (aq)

Molarity of HCl = number of moles / volume

Number of moles = Molarity of Hcl * volume

No of moles = 0.8 * 18.6 * 10^ (-3) = 14.88 * 10^ (-3)

From the equation one mole of HCl reacts with one mole of ammonia

Hence number of moles of ammonia = 14.88 * 10^ (-3)

From question volume of ammonia = 5 * 10^ (-3)

So it follows that Molarity of ammonia = number of moles of ammonia / volume

Molarity = 14.88 * 10^ (-3) / 5 * 10^ (-3) = 2.976 * 10^ (-3 - (-3))

Molarity = 2.976