What is the percent yield of a reaction in which 200. g of phosphorus trichloride reacts with excess water to form 91.0 g of hcl and aqueous phosphorous acid (h3po3) ?

Question

Chemistry

Emery Poole

11 November, 22:07

What is the percent yield of a reaction in which 200. g of phosphorus trichloride reacts with excess water to form 91.0 g of hcl and aqueous phosphorous acid (h3po3) ?

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Snoop · Answer 1

Answer is: yield of a reaction is 56,4%.

Chemical reaction: PCl₃ + 3H₂O → 3HCl + H₃PO₃.

m (PCl₃) = 200 g.

m (HCl) = 91,0 g.

n (PCl₃) = m (PCl₃) : M (PCl₃).

n (PCl₃) = 200 g : 137,33 g/mol.

n (PCl₃) = 1,46 mol.

n (HCl) = m (HCl) : M (HCl).

n (HCl) = 91 g : 36,45 g/mol.

n (HCl) = 2,47 mol.

From reaction: n (PCl₃) : n (HCl) = 1 : 3.

n (HCl) = 1,46 mol · 3 = 4,38 mol.

Yield of reaction: 2,47 mol : 4,38 mol · 100% = 56,4%.