What is the current in amperes if 1200 na + ions flow across a cell membrane in 3.5 μs? the charge on the sodium is the same as on an electron, but positive?

Charge = 1200 * 1.6 * 10^-19 = 1920 * 10^-19

Time = 3.5 µs = 3.5 * 10^-6 s

But Current = charge/time = (1920 * 10^-19) / (3.5 * 10^-6)

So Current becomes 548.5714 * 10^ (-19 - (-6))

So we have 548.5714 * 10^ (-19 + 6) = 548.5714 * 10^ (-13)

So we have 5.485714 * 10^ (-15)