A compound x of molecular formula c8h12 with no triple bonds reacts with one equivalent of h2 to give a new compound having molecular formula c8h14. what can be inferred about the structure of compound x?

The molecular formula given is C₈H₁₂, and it is also stated that it does not contain any triple bond and reacts with one equivalent H₂ to give a new compound with molecular formula C₈H₁₄.

First let us find the HDI (Hydrogen Deficiency Index) of this compound.

HDI = 2C + 2 + N - H - X / 2

So,

HDI = 2 (8) + 2 - 12 / 2

HDI = 16 + 2 - 12 / 2

HDI = 6 / 2

HDI = 3

Hence HDI 3 means, that our structure may contain following

1) 3 double bonds

2) 1 double bond and 1 triple bond

3) 3 Rings

4) 2 Rings and 1 double bond

5) 1 Ring and 2 double bonds

Hence, there are many possible isomers. But in statement it is given that it reacts with 1 equivalent H₂, means it contains only one double bond. So, according to my opinion our structure would contain 1 double bond and two rings as we are told in start that there is no triple bond. Hence, the possible structure is as follow along with reaction with 1 equivalent H₂.