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2 August, 06:36

It is necessary to have a 40% antifreeze solution in the radiator of a certain car. the radiator now has 70 liters of 20% solution. how many liters of this should be drained and replaced with 100% antifreeze to get the desired strength?

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  1. 2 August, 10:34
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    The answer is : 17.5 liters drained and replaced by 17.5 liters of 100% solution.

    x = amount drained and replaced

    (70-x) = remaining amount of 20% solution

    .20 (70-x) + 1.00 (x) =.40 (70)

    14 -.2x + 1x = 28

    1x -.2x = 28 - 14

    .8x = 14

    x = 14/.8

    x = 17,5 (17.5 liters drained and replaced by 17.5 liters of 100% solution)
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