A 98.0°C piece of cadmium (c=.850J/g°C) is placed in 150.0g of 37.0°C water. After sitting for a few minutes, both have a temperature of 38.6°C. What was the mass of the cadmium sample?

Question

Chemistry

Cassandra

29 November, 03:02

A 98.0°C piece of cadmium (c=.850J/g°C) is placed in 150.0g of 37.0°C water. After sitting for a few minutes, both have a temperature of 38.6°C. What was the mass of the cadmium sample?

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Quinn · Answer 1

The answer is 19.9 grams cadmium.

Assuming there was no heat leaked from the system, the heat q lost by cadmium would be equal to the heat gained by the water:

heat lost by cadmium = heat gained by the water

-qcadmium = qwater

Since q is equal to mcΔT, we can now calculate for the mass m of the cadmium sample:

-qcadmium = qwater

- (mcadmium) (0.850J/g°C) (38.6°C-98.0°C)) = 150.0g (4.18J/g°C) (38.6°C-37.0°C)

mcadmium = 19.9 grams