What is the theoretical yield of ammonia, in kilograms, that we can synthesize from 5.22 kg of h2 and 31.5 kg of n2?

The theoretical yield of a process is the maximum amount of product that could be produced from the process. It is the amount to be produced when the process is complete or all of the reactants are consumed by the reaction. To calculate, we need the chemical reaction of the process. For this case,

3H2 + N2 = 2NH3

We need to determine the limiting reactant.

5.22 kg H2 (1 kmol H2 / 2.02 kg H2) (1 kmol N2 / 3 kmol H2) (28.02 kg / 1 kmol) = 24.14 kg N2 needed

31.5 kg N2 (1 kmol N2 / 28.02 kg N2) (3 kmol H2 / 1 kmol N2) (2.02 kg / 1 kmol) = 6.81 H2 needed

Therefore, the limiting reactant would be hydrogen gas. We calculate the theoretical yield as follows:

5.22 kg H2 (1 kmol H2 / 2.02 kg H2) (2 kmol NH3 / 3 kmol H2) (17.04 kg / 1 kmol) = 29.36 kg NH3