Analysis of a compound indicates that it contians 1.04 g k, 0.70 g cr, and 0.86 g o. find its empirical formula. 1. k2cro3 2. kcro4 3. k2cro4 4. kcro3

Empirical formula of a chemical compound is the simplest positive integer ratio of atoms in the compound.

The first step is getting the number of moles of each.

Potassium - 1.04/39 = 0.0267

Chromium - 0.7 / 52 = 0.0135

Oxygen - 0.86/16 = 0.05375

Then we divide each with the smallest number,

0.0267/0.0135 = 1.98

0.0135/0.0135=1

0.05375/0.0135 = 3.98

Therefore the ratio is 2:1:4

Hence the empirical formula is K2CrO4