How many milliliters of. 45m hcl will neutralize 25ml of 1m koh?

The number of Ml of 0.45m HCl needed to neutralize 25 ml of 1 ml KOH is calculated as below

find the moles of KOH used = molarity x volume

= 1 x25 = 25 moles

write the reacting equation

KOH + HCL = KCl + H2O

by use of mole ratio between KOH to HCl which is 1:1 therefore the moles of 25 moles

volume of HCl = moles/molarity

25/0.45 = 55.6 ml of HCL

The balanced equation for the reaction is as follows;

HCl + KOH - - - > KCl + H₂O

stoichiometry of HCl to KOH is 1:1

number of KOH moles reacted - 1 mol/L x 0.025 L = 0.025 mol

according to 1:1 molar ratio

number of KOH moles reacted = number of HCl moles reacted

therefore number of HCl moles reacted - 0.025 mol

molarity of HCl is 0.45 M

since 0.45 mol are in 1000 mL

therefore 0.025 mol are in a volume of 0.025 mol / 0.45 mol/L = 55.5 mL

55.6 mL of HCl is required to neutralise