If 65.1L of N2 (g) is needed to properly inflate an airbag, how many grams of NaN3 (s) are needed for the reaction

The equation for this reaction is as follow,

2 NaN₂ (s) → 2 Na (s) + 3 N₂ (g)

According to equation,

67.2 L N₂ (3 moles) is produced by = 102 g (2 moles) NaN₂

So,

65.1 L N₂ will be produced by = X g of NaN₂

Solving for X,

X = (102 g * 65.1 L) : 67.2

X = 98.81 g of NaN₂

Result:

98.81 g of NaN₂ is required to produce 65.1 L N₂ to inflate airbag.