Solve the below problem.

How many liters of ammonia gas (NH3), can be formed from 54.1 liters of hydrogen gas (H2) at STP?

3H2 + N2 - - > 2NH3

Question options:

36.1 liters NH3

81.1 liters NH3

44.8 liters NH3

27.1 liters NH3

the balanced equation for the formation of ammonia is as follows

N₂ + 3H₂ - - > 2NH₃

stoichiometry of H₂ to NH₃ is 3:2

in gases number of moles of gas is directly proportional to volume of gases.

therefore molar ratio is equal to volume ratios.

this means volume ratio of H₂ to NH₃ is 3:2

volume of H₂ reacted - 54.1 L

if 3 L of H₂ forms - 2 L of NH₃

then 54.1 L of H₂ forms - 2/3 x 54.1 = 36.1 L of NH₃

volume of NH₃ formed is 36.1 L

44.8 I think ... I'm not so smart but I think so.