A student titrates an unknown amount of potassium hydrogen phthalate (khc8h4o4, abbreviated khp) with 20.46 ml of 0.1000 m naoh solution. khp has one acidic hydrogen. what mass (in grams) of khp was titrated by the sodium hydroxide solution?

Question

Chemistry

Aisha Malone

25 August, 20:34

A student titrates an unknown amount of potassium hydrogen phthalate (khc8h4o4, abbreviated khp) with 20.46 ml of 0.1000 m naoh solution. khp has one acidic hydrogen. what mass (in grams) of khp was titrated by the sodium hydroxide solution?

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Nelson Williamson · Answer 1

0.1000 M NaOH means 0.1 mole per litre so 20.46ml has 20.46/1000 x 0.1 = 0.002046 moles - now this many moles of KHP is 0.002046 x 204.22=0.4178 g KHP