What is the total number of moles (n) of electrons exchanged between the oxidizing agent and the reducing agent in the overall redox equation: 5 Ag (aq) + Mn2 (aq) + 4H20 () 5Ag (s) + MnO4 (aq) + 8H' (aq)

a. 1

b. 2

c. 3

d. 5 (

e.?

5 moles of electrons

Explanation:

The balance equation is as follow,

5 Ag ⁺ + Mn⁺² + 4 H ₂O → 5 Ag + MnO ₄⁻ + 8 H ⁺

Reduction of Ag:

Ag⁺ + 1 e⁻ → Ag

Or,

5 Ag⁺ + 5 e⁻ → 5 Ag

Oxidation of Mn:

Mn⁺² → MnO₄⁻ + 5 e⁻

Result:

Hence 5 moles of Ag⁺ accepts 5 electrons from 1 mole of Mn⁺².