What volume of chlorine gas at 45.3 c is needed to react with 14.2g of sodium to form nacl at 1.72 atm?

To determine the volume of chlorine gas that is needed, we need to first know the reaction. It is expressed as follows:

2Na + Cl2 = 2NaCl

Then, from the amount of NaCl to be produced, we calculate the moles of Cl2 needed.

14.2 g NaCl (1 mol / 58.44 g) (1 mol Cl2 / 2 NaCl) = 0.1215 mol Cl2

To determine the volume of the gas, we need an equation that would relate the number of moles to volume. There are a number of equation available but some are complex equations so we assume that it is an ideal gas. We use the equation:

PV = nRT

V = nRT / P

V = 0.1215 mol (0.08205 L-atm / mol-K) (45.3 + 273.15 K) / 1.72 atm

V = 1.85 L Cl2 gas