What is the molarity of a solution of calcium chloride which contains 33500mg of solute in total volume of 0.352L?

The molarity of a solution of CaCl2 is calculated as below

convert mm to g

1mg = 0.001 g

what about 33500 mg=? g

33500 x 0.001 = 33.5 g

find the moles of CaCl2 = mass/molar mass

=33.5 g / 111 g/mol = 0.3018 moles

molarity = moles/volume

=0.3018/0.352 = 0.857 M