To what volume will a 2.33 l sample of gas expand if it is heated from 30.0 ∘c to 300.0 ∘c?

According to Charle's Law,

V/T = constant

where

V = volume

T = absolute temperature.

The law holds when the pressure of an ideal gas is held constant while temperature changes.

V₁ = 2.33 L, initial volume

T₁ = 30°C = 30+273 K = 303 K, initial temperature

T₂ = 300°C = 300+273 K = 573 K, final temperature

The final volume, V₂, is given by

V₂/T₂ = V₁/T₁

V₂ = (573 K) * (2.33/303 L/K)

= 4.406 L

Answer: 4.41 L