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3 January, 02:56

Calculate the molar concentration of oh - ions in a 0.555 m solution of hypobromite ion (bro-; kb=4.0*10-6).

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  1. 3 January, 06:25
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    According to the reaction equation:

    and by using ICE table:

    BrO - + H2O → HBrO + OH-

    initial 0.555m 0 0

    change - X + X + X

    Equ (0.555-X) X X

    when Kb = [HBrO][OH-] / [BrO-]

    by substitution:

    4 x 10^-6 = X^2 / (0.555-X) by solving for X

    ∴ X = 0.00149

    ∴[OH-] = X = 0.00149 m
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