If 30g of HCl is dissolved and 10g of NaCl is produced, what is the theoretical yield of the experiment?

HCl + NaOH = NaCl + H₂O

m (HCl) = 30g

m' (NaCl) = 10g

M (HCl) = 36.46 g/mol

M (NaCl) = 58.44 g/mol

m (NaCl) / M (NaCl) = m (HCl) / M (HCl)

theoretical mass of sodium chloride

m (NaCl) = M (NaCl) m (HCl) / M (HCl)

m (NaCl) = 58.44*30/36.46=48.09 g

the practical yield of the reaction

w=m' (NaCl) / m (NaCl) = m' (NaCl) M (HCl) / M (NaCl) m (HCl)

w=10*36.46 / (58.44*30) = 0.2080 (20.80%)