How many grams of carbon dioxide are produced from the combustion of 1.3 moles of acetylene

Complete combustion of acetylene generated carbon dioxide and water. This can be represent by following reaction

2C2H2 + 5O2 → 4CO2 + 2H2O

(2 mole) (4 mole)

From the above balanced reaction, it can be seen that 2 mole of acetylene on complete combustion generates 4 moles of carbon dioxide

i. e. 2 mole of C2H2 ≡ 4 mole of CO2

∴ 1.3 mole of C2H2 ≡ (4 X 1.3) / 2 = 2.6 mole of CO2

Now, 1 mole of CO2 = 44 g

∴ 2.6 mole of CO2 = (44 X 2.6) = 114.4 g

Thus, 114.4 grams of carbon dioxide are produced from the combustion of 1.3 moles of acetylene