How many moles of h2so4 are needed to neutralize 1.56 moles of koh?

The balanced equation for the above neutralisation reaction is as follows;

2KOH + H₂SO₄ - - > K₂SO₄ + 2H₂O

stoichiometry of KOH to H₂SO₄ is 2:1

neutralisation is the reaction between H⁺ ions and OH⁻ ions to form water which is neutral

number of KOH moles - 1.56 mol

2 mol of KOH require 1 mol of H₂SO₄ for neutralisation

therefore 1.56 mol of KOH require - 1/2 x 1.56 mol = 0.78 mol

0.78 mol of H₂SO₄ are required for neutralisation