A 10.0ml sample of calcium hydroxide solution requirewd 26.85ml of 0.225 m hydrochoric acid for neutralization. calculate the nolar concentration of the bsae

The balanced equation for the acid base reaction is as follows

Ca (OH) ₂ + 2HCl - - - > CaCl₂ + 2H₂O

stoichiometry fo Ca (OH) ₂ to HCl is 1:2

number of HCl moles reacted - concentration of HCl x volume

number of HCl moles - 0.225 mol/L x 26.85 x 10⁻³ L = 6.041 x 10⁻³ mol

according to molar ratio

2 mol of HCl reacts with 1 mol of Ca (OH) ₂

therefore 6.041 x 10⁻³ mol of HCl reacts with - 6.041 x 10⁻³ / 2 mol = 3.021 x 10⁻³ mol

number of Ca (OH) ₂ moles in 10.0 mL - 3.021 x 10⁻³ mol

therefore Ca (OH) ₂ moles in 1000 mL - 3.021 x 10⁻³ mol / (10.0 x 10⁻³ L) = 0.302 mol/L

molarity of Ca (OH) ₂ - 0.302 M