How many liters of H2O are produces @ STP by the combustion of 30g of CH4 CH4+2O2---> CO2 + 2H2O

Question

Chemistry

Sidney Arnold

24 December, 22:57

How many liters of H2O are produces @ STP by the combustion of 30g of CH4 CH4+2O2---> CO2 + 2H2O

+5

Answers (1)

Know the Answer?

Harrison White · Answer 1

CH4+2O2---> CO2 + 2H2O

M (CH4) = 16.0 g/mol

30g CH4*1mol/16.0 g - mol of CH4

30g CH4 * (1mol/16.0 g) * (2 mol H2O/1 mol CH4) = 15 mol H2O

30g CH4 * (1mol/16.0 g) * (2 mol H2O/1 mol CH4) * 22.4L/1mol=84 L H2O as gas, but at STP water should be liquid, so

15 mol H2O*18g H2O/1 mol=270g of H2O

270g*1ml/1g = 270 ml = 0.27 L of liquid water, in reality it should be like this,

but I do not know what people who created this problem wanted H2O as liquid or as gas