Write the ksp expression for the sparingly soluble compound silver chromate, ag2cro4.

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Chemistry

Laci

22 April, 19:37

Write the ksp expression for the sparingly soluble compound silver chromate, ag2cro4.

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Brayden Boyd · Answer 1

Chemical reaction (dissociation) of silver chromate in water:

Ag₂CrO₄ (s) → 2Ag⁺ (aq) + CrO₄²⁻ (aq).

Ksp (Ag₂CrO₄) = [Ag⁺]²·[CrO₄²⁻].

[ CrO₄²⁻] = x.

[ Ag⁺] = 2[CrO₄²⁻] = 2x

Ksp = (2x) ² · x = 4x³.

Ksp is the solubility product constant for a solid substance dissolving in an aqueous solution.

[Ag⁺] is equilibrium concentration of silver cations.

[CrO₄²⁻] is equilibrium concentration of chromate anions.