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27 August, 06:55

How many grams of calcium chloride are dissolved in 5.65 liters of a 0.11 m solution of calcium choride?

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  1. 27 August, 09:29
    0
    C = 0.11 mol

    V = 5.65 L

    n = ?

    n = C*V

    n = 0.11 * 5.65

    n = 0.622 mols

    1 mol of CaCl2 = 40 + 2*35.5 = 111 grams

    0.622 mol = x

    x = 111 * 0.622

    x = 69.0 grams CaCl2
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