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16 August, 23:16

00 ml of 0.425 m h2so4 solution is required to completely neutralize 23.9 ml of koh solution. what is the molarity of the koh solution

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  1. 17 August, 01:15
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    00 mL? I believe that you have erroneously pasted the question here.

    Anyway, let us continue computing for the molarity of KOH but i will just use a variable "A" for the volume of H2SO4 solution.

    The complete balanced reaction is:

    H2SO4 + 2KOH - - > K2SO4 + 2H2O

    We see that 2 moles of KOH is needed for every mole of H2SO4. So calculate the moles of H2SO4.

    moles H2SO4 = 0.245 M * (A / 1000) = 2.45x10^-4 A

    So the number of moles of KOH is:

    moles KOH = 2.45x10^-4 A * 2

    moles KOH = 4.90x10^-4 A

    So the molarity of KOH is:

    Molarity KOH = 4.90x10^-4 A / (0.0239 L)

    Molarity KOH = 0.0205 * A

    Simply multiply 0.0205 by the correct volume of H2SO4 in ml
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