At 25 ∘c, kp = 25 for the reaction h2 (g) + i2 (g) ⇌2hi (g). at equilibrium, the partial pressure of both h2 and i2 is 0.296 atm. what is the partial pressure of hi at equilibrium?

Question

Chemistry

Bullock

Today, 08:56

At 25 ∘c, kp = 25 for the reaction h2 (g) + i2 (g) ⇌2hi (g). at equilibrium, the partial pressure of both h2 and i2 is 0.296 atm. what is the partial pressure of hi at equilibrium?

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Answers (1)

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Amy Lucas · Answer 1

According to this reaction:

H2 (g) + i2 (g) ↔ 2 HI (g)

initial 0.296 0.296 0

Change - X - X + 2X

Equ (0.296-X) (0.296-X) 2 X

when Kp = p (HI) ^2/p (H2) P (I2)

25 = (2X) ^2 / (0.296-X) ^2

X = 0.49

∴ P (HI) = 0.49 atm