What is the ph of a 7.5*10-3m oh - solution?

ph=?

We will assume complete dissociation.

Since we have the molarity of OH solution, we can calculate the p (OH) as follows:

p (OH) = - log (molarity of OH) = - log (7.5*10-3) = 2.1249

It is known that: p (H) + p (OH) = 14

Therefore, p (H) can be calculated as follows:

p (H) = 14 - p (OH) = 14 - 2.1249 = 11.875