Determine the molarity of a solution made by dissolving 11.7 g of NaNO3 in water where the final volume of the solution is 250.0 mL.

Molarity is defined as the number of moles of solute in 1 L solution.

we have been given the mass of NaNO₃ dissolved in 250.0 mL

number of moles of NaNO₃ - 11.7 g / 85 g/mol = 0.138 mol

number of NaNO₃ moles in 250.0 mL - 0.138 mol

since molarity is the number of moles in 1 L

number of NaNO₃ moles in 1000 mL - 0.138 mol / 250.0 mL x 1000mL/L = 0.552 mol

molarity of NaNO₃ is 0.552 M