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4 December, 03:18

A mass of 21.5 grams of calcium hydroxide reacts with an excess of phosphoric acid. what mass of calcium phosphate could be recovered from solution?

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  1. 4 December, 06:31
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    The balanced equation for the above reaction is as follows;

    3Ca (OH) ₂ + 2H₃PO₄ - - - > Ca₃ (PO₄) ₂ + 6H₂O

    stoichiometry of Ca (OH) ₂ to Ca₃ (PO₄) ₂ is 3:1

    Since Ca (OH) ₂ is the limiting reactant, amount of Ca₃ (PO₄) ₂ formed depends on the amount of Ca (OH) ₂ present

    Number of Ca (OH) ₂ reacted - 21.5 g/74 g/mol = 0.29 mol

    Therefore number of Ca₃ (PO₄) ₂ moles formed - 0.29 mol/3 = 0.0967 mol

    Mass of Ca₃ (PO₄) ₂ formed - 0.0967 mol x 310 g/mol = 30.0 g
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