How many milliliters of 0.111 m hclo4 solution are needed to neutralize 50.00 ml of 0.0789 m naoh?

HClO₄ is a strong acid and NaOH is a strong base. Therefore they completely dissociate in the solution.

NaOH + HClO₄ - - - > NaClO₄ + H₂O

stoichiometry of acid to base is 1:1

amount of NaOH moles reacted - 0.0789 M / 1000 mL/L x 50.00 mL

= 0.00395 mol

Amount of HClO₄ moles reacted = 0.00395 mol

Molarity of HClO₄ is 0.111 M

Volume of HClO₄ l containing 0.111 mol - 1 L

Therefore volume of HClO₄ containing 0.00395 mol - 1/0.111 x 0.00395 = 0.0356 L

Volume of HClO₄ - 35.6 mL